College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 137: 36

Answer

(a) 735 N (b) 735 N (c) 885 N

Work Step by Step

(a) If the elevator is at rest, $W=mg=75.0\,kg\times9.80\,m/s^{2}=735\,N$ (b) Also, if it is moving up or down with a constant velocity, $W=mg=735\,N$ (c) When it accelerates up, $W=m(g+a)=75.0\,kg(9.80\,m/s^{2}+2.00\,m/s^{2})=885\,N$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.