#### Answer

(a) (1) less than the weight of the object.
(b) Weight= 98 N, Normal force= 85 N.

#### Work Step by Step

(a) $W=mg$
$N=mg\cos\theta$
As the plane is inclined, $\theta$ can't be 0. Therefore, $\cos\theta$ will always be less than 1. In other words, $mg\cos\theta\lt mg$
Or $N\lt W$. The normal force is (1) less than the weight of the object if it is placed in an inclined plane.
(b) $Weight=mg=10\,kg\times9.8\,m/s^{2}=98\,N$
Normal force $N=mg\cos\theta =10\,kg\times9.8\,m/s^{2}\times\cos 30^{\circ}=85\,N$