## College Physics (7th Edition)

$3.64m/s^{2}$
$t=\frac{110}{2\times25cos20^{\circ}}$ Again, $v=u+at$ $0=25sin20^{\circ}-at$ $a=\frac{25sin20^{\circ}}{t}$ $a=\frac{2\times25\times25\times sin20^{\circ} cos20^{\circ}}{110}$ $a=\frac{25\times25\times sin40^{\circ}}{110}$ $a=3.64m/s^{2}$