College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 99: 56

Answer

$3.64m/s^{2}$

Work Step by Step

$t=\frac{110}{2\times25cos20^{\circ}}$ Again, $v=u+at$ $0=25sin20^{\circ}-at$ $a=\frac{25sin20^{\circ}}{t}$ $a=\frac{2\times25\times25\times sin20^{\circ} cos20^{\circ}}{110}$ $a=\frac{25\times25\times sin40^{\circ}}{110}$ $a=3.64m/s^{2}$
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