College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 99: 54


Minimum launch speed to complete the jump $=5.56m/s$

Work Step by Step

$S=ut+\frac{1}{2}at^{2}$ $4=0+4.9t^{2}$ $t=0.9s$ So, required horizontal speed = $\frac{5}{0.9}m/s=5.56m/s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.