#### Answer

a). $\theta=46^{\circ}$
b). The plane has traversed 1460m.

#### Work Step by Step

a) $S=ut+\frac{1}{2}gt^{2}$
or, $1500=0+0.5\times9.8t^{2}$
$t=17.5s$
Now, $300km/hr=83.3m/s$,
Horizontal distance covered=$17.5\times83.3=1460m$
Thus, $\theta=tanx^{-1}\frac{1500}{1460}\approx46^{\circ}$
b) Horizontal distance travelled = 1460m.