## College Physics (7th Edition)

(a) n=2, $r_{2}= 0.2116 nm$ (b) n=2, $r_{4}= 0.8464 nm$ (c) n=5, $r_{5}= 1.3225 nm$
orbital radii for for the hydrogen atom is given by $r_{n}=0.0529\times n^{2} nm$ where n=1,2,3........are states of electron (principal quantum number ) (a) n=2, $r_{2}=0.0529\times 2^{2} nm$= $0.2116 nm$ (b) n=2, $r_{4}=0.0529\times 4^{2} nm$= $0.8464 nm$ (c) n=5, $r_{5}=0.0529\times 5^{2} nm$= $1.3225 nm$