Answer
(a) n=2, $r_{2}= 0.2116 nm $
(b) n=2, $r_{4}= 0.8464 nm $
(c) n=5, $r_{5}= 1.3225 nm $
Work Step by Step
orbital radii for for the hydrogen atom is given by
$r_{n}=0.0529\times n^{2} nm$
where n=1,2,3........are states of electron (principal quantum number )
(a) n=2, $r_{2}=0.0529\times 2^{2} nm$= $0.2116 nm $
(b) n=2, $r_{4}=0.0529\times 4^{2} nm$= $0.8464 nm $
(c) n=5, $r_{5}=0.0529\times 5^{2} nm$= $1.3225 nm $
