College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 27 - Quantum Physics - Learning Path Questions and Exercises - Exercises - Page 936: 30

Answer

change in wavelength will be $\Delta \lambda=0.3256nm$

Work Step by Step

given that scattering angle $\theta=30^{0}$ Wavelength shift or Compton shift is given by $\Delta \lambda= \lambda- \lambda_{0}=\lambda_{C} (1-cos\theta)$ $\Delta \lambda= \lambda- \lambda_{0}=\lambda_{C} (1-cos30^{0})$ $\Delta \lambda=\lambda_{C} (1-0.8660)=0.134\lambda_{C}$ for scattering by electron $\lambda_{C}=\frac{h}{m_{e}c}=2.43\times10^{-3}nm$ change in wavelength will be $\Delta \lambda=0.134\times2.43\times10^{-3}nm=0.3256nm$
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