Chapter 2 - Kinematics: Description of Motion - Learning Path Questions and Exercises - Exercises - Page 61: 29

$a). 16.67s$ $b). 277.9m$ $c). 33.34 m/s$

a). $60km/hr=60\times \frac{1000m}{3600s}=16.67m/s$ $16.67t=0+\frac{1}{2}\times at^{2}$ $16.67t=t^{2}$ (a=$2m/s^{2})$ So, t=16.67s b). Distance travelled = $\frac{1}{2}\times 2\times 16.67^{2}=277.9 m$ c). Velocity of sports car at that time = $0+at=2\times 16.67=33.34 m/s$