College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 2 - Kinematics: Description of Motion - Learning Path Questions and Exercises - Exercises - Page 61: 27

Answer

$-2.1 m/s^{2}$

Work Step by Step

Change in velocity = $30-75 = -45 km/hr = -45\times \frac{1000m}{3600s}=-12.5 m/s$ Average Acceleration = $-\frac{12.5 m/s}{6 s}= -2.1 m/s^{2}$
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