Answer
$2.31 m/s^{2}$
Work Step by Step
The magnitude of average acceleration =$\frac{65-15}{6}\times\frac{1000}{3600}=2.31 m/s^{2}$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 2 - Kinematics: Description of Motion - Learning Path Questions and Exercises - Exercises - Page 61: 23
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