College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 2 - Kinematics: Description of Motion - Learning Path Questions and Exercises - Exercises - Page 61: 24

Answer

$6.88m/s^{2}$

Work Step by Step

$60 mi/hr = 60\times\frac{1609m}{3600s}=26.82m/s$ So, average acceleration = $\frac{26.82m/s}{3.9s}=6.88m/s^{2}$
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