Answer
$1.2 \,\Omega$
Work Step by Step
$P=\frac{V^{2}}{R}$ where $P$ is the power, $V$ is the voltage and $R$
is the resitance.
$\implies R=\frac{V^{2}}{P}=\frac{(240\,V)^{2}}{50\times10^{3}\,W}=1.2\,\Omega$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 17 - Electric Current and Resistance - Learning Path Questions and Exercises - Exercises - Page 620: 39
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