College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 17 - Electric Current and Resistance - Learning Path Questions and Exercises - Exercises - Page 620: 37

Answer

$2.0\times10^{3}$ W

Work Step by Step

Resistance R= 12 $\Omega$ Current I= 13 A Power P= $I^{2}R= (13A)^{2}12\Omega= 2.0\times10^{3}W$
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