College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 17 - Electric Current and Resistance - Learning Path Questions and Exercises - Exercises - Page 620: 25

Answer

a). $0.13ohm$ b). $0.038ohm$

Work Step by Step

a). Resistivity at $380^{\circ}C$ is $=p(1+alpha\times\Delta T)=10^{-7}(1+6.51\times10^{-3}\times380)=3.474\times10^{-7}ohm-m$ So, resistance at $380^{\circ}C$ = $p\frac{L}{A}=\frac{3.474\times10^{-7}\times0.75}{2\times10^{-6}}=0.13ohm$ b). Resistance of the coil when stove is off is equal to that when in room temperature, which is $=p\frac{L}{A}=\frac{10^{-7}\times0.75}{2\times10^{-6}}=0.038ohm$
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