College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 17 - Electric Current and Resistance - Learning Path Questions and Exercises - Exercises - Page 620: 35

Answer

144 $\Omega$

Work Step by Step

Given: P= 100 W, V= 120 V Recall: $P=\frac{V^{2}}{R}$ or $R= \frac{V^{2}}{P}$ Substitute: $R= \frac{(120V)^{2}}{100W}=144 \Omega$
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