College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 17 - Electric Current and Resistance - Learning Path Questions and Exercises - Exercises - Page 619: 8


6.1 s

Work Step by Step

Recall that $I=\frac{q}{t}$ Rearranging the equation, we have $t= \frac{q}{I}$ Given that q= 3.50 C and I= 0.57 A. Plugging in the values, we get $t= \frac{3.50C}{0.57A}$= 6.1 seconds.
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