College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 17 - Electric Current and Resistance - Learning Path Questions and Exercises - Exercises - Page 619: 10

Answer

$4.7\times10^{20}$ electrons.

Work Step by Step

$I=\frac{q}{t}\implies q=It=50\,A\times1.5\,s=75\,C$ Number of electrons=$\frac{q}{e}=\frac{75\,C}{1.6\times10^{-19}\,C/electron}$$=4.7\times10^{20}\,electrons$
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