College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 17 - Electric Current and Resistance - Learning Path Questions and Exercises - Exercises - Page 619: 18



Work Step by Step

Given internal resistance = $0.15 ohm$ current delivered by battery = $I=1.5A$ Value of external resistor $R=5 Ohm$ Emf of battery = $E=V+Ir$ $V=IR=1.5\times5=7.5V$ Emf of the battery =$7.5+1.5\times0.15=7.5+0.225=7.725V$
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