Answer
$7.725V$
Work Step by Step
Given internal resistance = $0.15 ohm$
current delivered by battery = $I=1.5A$
Value of external resistor $R=5 Ohm$
Emf of battery = $E=V+Ir$
$V=IR=1.5\times5=7.5V$
Emf of the battery =$7.5+1.5\times0.15=7.5+0.225=7.725V$