College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 17 - Electric Current and Resistance - Learning Path Questions and Exercises - Exercises - Page 619: 11


56 s

Work Step by Step

$I_{1}=\frac{q_{1}}{t_{1}}=\frac{20\,C}{1.25\times60\,s}=0.27\,A$ Given: $q_{2}=30\,C,$ $I_{2}=2I_{1}=2\times0.27\,A=0.54\,A$ Therefore, $t_{2}=\frac{q_{2}}{I_{2}}=\frac{30\,C}{0.54\,A}=56\,s$
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