College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 15 - Electric Charge, Forces, and Fields - Learning Path Questions and Exercises - Multiple Choice Questions - Page 554: 9

Answer

(c) it is reduced to $\frac{1}{9}$th its original value.

Work Step by Step

$F=k\frac{q_{1}q_{2}}{r^{2}}$ So, if r is tripled, then F will be $\frac{1}{3^{2}}=\frac{1}{9}$th of the original value as evident from the equation above.
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