College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 15 - Electric Charge, Forces, and Fields - Learning Path Questions and Exercises - Multiple Choice Questions - Page 554: 11

Answer

(c) it is reduced to one-ninth of its original value.

Work Step by Step

$F=k\frac{q_{1}q_{2}}{r^{2}}$ When the distance is tripled, New Force=$k\frac{q_{1}q_{2}}{(3r)^{2}}=\frac{1}{9}F$ Hence, (c) is the answer.
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