College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 15 - Electric Charge, Forces, and Fields - Learning Path Questions and Exercises - Multiple Choice Questions - Page 554: 10

Answer

(a) increase each charge by 3 times.

Work Step by Step

$F_{1}=k\frac{q_{1}q_{2}}{r^{2}}$ Suppose, if we triple each of the charges, and distance is also tripled, then the new force, $F_{2}=k\frac{3q_{1}3q_{2}}{(3r)^{2}}=k\frac{q_{1}q_{2}}{r^{2}}=F_{1}$ Hence (a) is the answer.
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