College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Review & Synthesis: Chapters 6-8 - MCAT Review - Page 326: 7


The correct answer is: B. $1500~W$

Work Step by Step

The total work done is equal to the apparent increase in gravitational potential energy: $U_g = mgh$ $U_g = mgd~sin~\theta$ $U_g = mgvt~sin~\theta$ $U_g = (100~kg)(10~m/s^2)(3~m/s)(300~s)~sin~30^{\circ}$ $U_g = 4.5\times 10^5~J$ This energy is expended in a time of 300 seconds. We can find the power output: $power = \frac{energy}{time} = \frac{4.5\times 10^5~J}{300~s} = 1500~W$ The correct answer is: B. $1500~W$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.