College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Review & Synthesis: Chapters 6-8 - MCAT Review - Page 326: 1


The correct answer is: (D) $0.6~kg~m/s$

Work Step by Step

We can find the change in velocity of the projectile: $\Delta v = v_f - v_0 = (-1.0~m/s)-(2.0~m/s) = -3.0~m/s$ We can use the magnitude of the change in velocity to find the change in momentum of the projectile: $\Delta p = m \Delta v = (0.2~kg)(3.0~m/s) = 0.6~kg~m/s$ By conservation of momentum, the bin receives this same magnitude of momentum. The correct answer is: (D) $0.6~kg~m/s$
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