#### Answer

The correct answer is:
(D) $0.6~kg~m/s$

#### Work Step by Step

We can find the change in velocity of the projectile:
$\Delta v = v_f - v_0 = (-1.0~m/s)-(2.0~m/s) = -3.0~m/s$
We can use the magnitude of the change in velocity to find the change in momentum of the projectile:
$\Delta p = m \Delta v = (0.2~kg)(3.0~m/s) = 0.6~kg~m/s$
By conservation of momentum, the bin receives this same magnitude of momentum.
The correct answer is:
(D) $0.6~kg~m/s$