College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Review & Synthesis: Chapters 6-8 - MCAT Review - Page 326: 2


The correct answer is: D. $6.5~N/m$

Work Step by Step

We can find the spring constant: $kx = mg$ $k = \frac{mg}{x}$ $k = \frac{(0.10~kg)(9.80~m/s^2)}{0.15~m}$ $k = 6.5~N/m$ The correct answer is: D. $6.5~N/m$
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