## College Physics (4th Edition)

The correct answer is: C. $0.54~MJ$
The total work done is equal to the apparent increase in gravitational potential energy: $U_g = mgh$ $U_g = mgd~sin~\theta$ $U_g = mgvt~sin~\theta$ $U_g = (90~kg)(10~m/s^2)(2~m/s)(600~s)~sin~30^{\circ}$ $U_g = 5.4\times 10^5~J$ $U_g = 0.54~MJ$ The correct answer is: C. $0.54~MJ$