College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Review & Synthesis: Chapters 6-8 - MCAT Review - Page 326: 6

Answer

The correct answer is: C. $0.54~MJ$

Work Step by Step

The total work done is equal to the apparent increase in gravitational potential energy: $U_g = mgh$ $U_g = mgd~sin~\theta$ $U_g = mgvt~sin~\theta$ $U_g = (90~kg)(10~m/s^2)(2~m/s)(600~s)~sin~30^{\circ}$ $U_g = 5.4\times 10^5~J$ $U_g = 0.54~MJ$ The correct answer is: C. $0.54~MJ$
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