College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 229: 46


The ratio $~~\frac{U_{perigee}}{U_{apogee}}~~~$ is equal to $~~2$

Work Step by Step

We can find the ratio of $\frac{U_{perigee}}{U_{apogee}}$: $\frac{U_{perigee}}{U_{apogee}} = \frac{-\frac{G~M_E~m}{2~R_E}}{-\frac{G~M_E~m}{4~R_E}}$ $\frac{U_{perigee}}{U_{apogee}} = \frac{4~R_E}{2~R_E}$ $\frac{U_{perigee}}{U_{apogee}} = 2$ The ratio $~~\frac{U_{perigee}}{U_{apogee}}~~~$ is equal to $~~2$.
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