## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 6 - Problems - Page 229: 38

#### Answer

The car reaches a highest point of 25.4 meters above the bottom of the hill.

#### Work Step by Step

We can use conservation of energy to find the highest point the car reaches on the hill (where we can assume that the kinetic energy is zero): $U_2+KE_2 = U_1+KE_1$ $mgh_2+0 = mgh_1+\frac{1}{2}mv_1^2$ $h_2 = h_1+\frac{v_1^2}{2g}$ $h_2 = (5.0~m)+\frac{(20.0~m/s)^2}{(2)(9.80~m/s^2)}$ $h_2 = 25.4~m$ The car reaches a highest point of 25.4 meters above the bottom of the hill.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.