College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 229: 36

Answer

The highest point is 1.925 meters above the ground.

Work Step by Step

We can use conservation of energy to find the highest point (where we can assume that the kinetic energy is zero): $U_2+KE_2 = U_1+KE_1$ $mgh_2+0 = mgh_1+\frac{1}{2}mv_1^2$ $h_2 = h_1+\frac{v_1^2}{2g}$ $h_2 = (0.70~m)+\frac{(4.9~m/s)^2}{(2)(9.80~m/s^2)}$ $h_2 = 1.925~m$ The highest point is 1.925 meters above the ground.
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