## College Physics (4th Edition)

We can use conservation of energy to find the highest point (where we can assume that the kinetic energy is zero): $U_2+KE_2 = U_1+KE_1$ $mgh_2+0 = mgh_1+\frac{1}{2}mv_1^2$ $h_2 = h_1+\frac{v_1^2}{2g}$ $h_2 = (0.70~m)+\frac{(4.9~m/s)^2}{(2)(9.80~m/s^2)}$ $h_2 = 1.925~m$ The highest point is 1.925 meters above the ground.