College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 229: 43


The escape speed from the planet is 60.0 km/s

Work Step by Step

Note that the gravitational field around at a planet's surface is: $\sqrt{\frac{GM_p}{R_p^2}}$ We can find the escape speed from the planet: $v = \sqrt{\frac{2GM_p}{R_p}}$ $v = \sqrt{\frac{(GM_p)~(2R_p)}{R_p^2}}$ $v = \sqrt{(30.0~m/s^2)(2)(6.00\times 10^7~m)}$ $v = 6.00\times 10^4~m/s = 60.0~km/s$ The escape speed from the planet is 60.0 km/s.
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