## College Physics (4th Edition)

The two mules together do $2.12\times 10^5~J$ of work on the barge.
We can find the work done by the two mules on the barge: $Work = F~d~cos~\theta$ $Work = (2)(1000~N)~(150~m)~cos~45^{\circ}$ $Work = 2.12\times 10^5~J$ The two mules together do $2.12\times 10^5~J$ of work on the barge.