College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 227: 17


The work done by friction is $-552.5~J$

Work Step by Step

The total work done by gravity $W_g$ and friction $W_f$ on the skateboarder is equal to the skateboarder's change in kinetic energy. We can find the work done by friction: $W_g+W_f = \frac{1}{2}mv^2$ $W_f = \frac{1}{2}mv^2 - W_g$ $W_f = \frac{1}{2}mv^2 - mgh$ $W_f = \frac{1}{2}(65.0~kg)(9.00~m/s)^2 - (65.0~kg)(9.80~m/s^2)(5.00~m)$ $W_f = -552.5~J$ The work done by friction is $-552.5~J$
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