## College Physics (4th Edition)

The towrope does $12,960~J$ of work on the water-skier.
We can find the work done by the towrope on the water-skier: $Work = F~d~cos~\theta$ $Work = (240~N)~(54~m)~cos~0^{\circ}$ $Work = 12,960~J$ The towrope does $12,960~J$ of work on the water-skier.