## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 6 - Problems - Page 227: 4

#### Answer

The towrope does $12,960~J$ of work on the water-skier.

#### Work Step by Step

We can find the work done by the towrope on the water-skier: $Work = F~d~cos~\theta$ $Work = (240~N)~(54~m)~cos~0^{\circ}$ $Work = 12,960~J$ The towrope does $12,960~J$ of work on the water-skier.

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