College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 227: 18


The work done by the wall is $-4170~J$

Work Step by Step

The work done by the wall on the skater is equal to the skater's change in kinetic energy. We can find the work done by the wall: $Work = KE_2-KE_1$ $Work = 0-\frac{1}{2}mv^2$ $Work = -\frac{1}{2}(69.0~kg)(11.0~m/s)^2$ $Work = -4170~J$ The work done by the wall is $-4170~J$
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