Answer
The work done every 10.0 seconds is 80.0 joules.
Work Step by Step
Note that the combined voltage of the two batteries is $4.00~V$
We can find the power:
$P = \frac{V^2}{R}$
$P = \frac{(4.00~V)^2}{2.00~\Omega}$
$P = 8.00~W$
We can find the work done in 10.0 seconds:
$Work = P~t = (8.00~W)(10.0~s) = 80.0~J$
The work done every 10.0 seconds is 80.0 joules.
