College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 18 - Problems - Page 702: 63


$I = 0.5~A$

Work Step by Step

We can find the current: $P = (I)~(\Delta V)$ $I = \frac{P}{\Delta V}$ $I = \frac{60.0~W}{120~V}$ $I = 0.5~A$
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