College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 18 - Problems - Page 702: 64


$R = 360~\Omega$

Work Step by Step

We can find the resistance: $P = \frac{V^2}{R}$ $R = \frac{V^2}{P}$ $R = \frac{(120~V)^2}{40.0~W}$ $R = 360~\Omega$
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