College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 18 - Problems - Page 702: 66


$P = 1.125~W$

Work Step by Step

We can find the maximum power consumed: $P = (I)~\times (\Delta V)$ $P = (0.250~A)(1.50~V+1.50~V+1.50~V)$ $P = (0.250~A)(4.50~V)$ $P = 1.125~W$
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