## College Physics (4th Edition)

The amount of energy dissipated by air resistance is $563,400~J$
We can find the initial gravitational potential energy: $U_g = mgh$ $U_g = (64~kg)(9.80~m/s^2)(900~m)$ $U_g = 564,480~J$ We can find the kinetic energy just before reaching the ground: $K = \frac{1}{2}mv^2$ $K = \frac{1}{2}(64~kg)(5.8~m/s)^2$ $K = 1076.5 ~J$ The amount of energy dissipated by air resistance is the difference between the initial potential energy and the final kinetic energy: $U_g- K = 564,480~J - 1076.5~J = 563,400~J$ The amount of energy dissipated by air resistance is $563,400~J$