#### Answer

The amount of energy dissipated by air resistance is $563,400~J$

#### Work Step by Step

We can find the initial gravitational potential energy:
$U_g = mgh$
$U_g = (64~kg)(9.80~m/s^2)(900~m)$
$U_g = 564,480~J$
We can find the kinetic energy just before reaching the ground:
$K = \frac{1}{2}mv^2$
$K = \frac{1}{2}(64~kg)(5.8~m/s)^2$
$K = 1076.5 ~J$
The amount of energy dissipated by air resistance is the difference between the initial potential energy and the final kinetic energy:
$U_g- K = 564,480~J - 1076.5~J = 563,400~J$
The amount of energy dissipated by air resistance is $563,400~J$