College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 14 - Problems - Page 533: 2

Answer

An internal energy of $1029~J$ is produced per kilogram.

Work Step by Step

The increase in internal energy is equal to the initial gravitational potential energy of the water at a height of 105 meters: $\Delta E = mgh$ $\Delta E = (1.0~kg)(9.80~m/s^2)(105~m)$ $\Delta E = 1029~J$ An internal energy of $1029~J$ is produced per kilogram.
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