## College Physics (4th Edition)

An internal energy of $149~J$ is generated.
We can convert the speed to units of $m/s$: $v = 162~km/h \times \frac{1000~m}{1~km} \times \frac{1~h}{3600~s} = 45~m/s$ The increase in internal energy is equal to the initial kinetic energy of the ball: $\Delta E = \frac{1}{2}mv^2$ $\Delta E = \frac{1}{2}(0.1475~kg)(45~m/s)^2$ $\Delta E = 149~J$ An internal energy of $149~J$ is generated.