## College Physics (4th Edition)

An internal energy of $4900~J$ is generated.
The increase in internal energy is equal to the initial kinetic energy of the bullet: $\Delta E = \frac{1}{2}mv^2$ $\Delta E = \frac{1}{2}(0.020~kg)(7.00\times 10^2~m/s)^2$ $\Delta E = 4900~J$ An internal energy of $4900~J$ is generated.