Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 8 - Exercises and Problems - Page 147: 24

Answer

Please see the work below.

Work Step by Step

We know that $U=Gm_{sun}m_{earth}(\frac{1}{r_2}-\frac{1}{r_1})$ We plug in the known values to obtain: $U=(6.67\times 10^{-11})(1.99\times 10^{23})(5.97\times 10^{24})(\frac{1}{147\times 10^9}-\frac{1}{152\times 10^9})$ $U=1.8\times 10^{32}J$
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