Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 8 - Exercises and Problems - Page 147: 20

Answer

Please see the work below.

Work Step by Step

We know that $\frac{T_{mars}^2}{T_{earth}^2}=(\frac{r_{mars}}{r_{earth}})^3$ This can be rearranged as: $T_{mars}=\sqrt{(\frac{r_{mars}}{r_{earth}})^3}T_{earth}$ $T_{mars}=\sqrt{(1.52)^3}T_{earth}$ $T_{mars}=(1.874 years)(365.25)=680days$
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