Essential University Physics: Volume 1 (4th Edition)

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 3 - Exercises and Problems - Page 52: 87


Please see the work below.

Work Step by Step

We know that $x=\frac{v_{\circ}^2}{g} sin (2\theta)$ After differentiating, we obtain: $x^{\prime}=(\frac{v_{\circ}^2}{g})(-2cos(2\theta))$ as $x^{\prime}=0$ $\implies cos(2\theta)=0$ $2\theta=90$ $\theta=45^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.