Answer
$77.2\space m$
Work Step by Step
Please see the attached image first.
We can write, $Acceleration\space (a)=\frac{V^{2}}{r}$ in rotational motion.
Let's plug known values into this equation.
$0.825\times9.8\space m/s^{2}=\frac{(90\times1000\times\frac{1}{3600}\space m/s)^{2}}{r}$
$r=\frac{625}{8.1}\space m=77.2\space m$
Driver has to start swerving from 77.2 m far from the truck
