Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 3 - Exercises and Problems - Page 52: 75


70.416 kilometers per hour

Work Step by Step

In a problem earlier in the chapter, we actually solved for an equation that modeled this exact problem. The equation is: $v_0=\sqrt{xg}=\sqrt{(39)(9.81)}=19.5599\ m/s \times 3.6 = \fbox{70.416 kilometers per hour}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.