Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 14 - Exercises and Problems - Page 272: 67

Answer

$r_2 = 6.32 \ m$

Work Step by Step

We have to find the distance at which the value of the log function will be half of what it is currently. Thus, we find: $.5 = log(\frac{r_2}{r_1}) \\ .5 = log(\frac{r_2}{2})\\r_2 = 6.32 \ m$
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