Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 14 - Exercises and Problems - Page 272: 64

Answer

a) $ I =10^{-5.5}$ b) $I = 10^{-12.5}$

Work Step by Step

We use the equation for intensities to find: a) $65 = 10log(\frac{I}{10^{-12}}) \\ I =10^{-5.5}$ b) $-5 = 10log(\frac{I}{10^{-12}}) \\ I = 10^{-12.5}$
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