Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 14 - Exercises and Problems - Page 272: 61

Answer

$L_0=\frac{5}{7}L_f$

Work Step by Step

a) While there is a way to use complex math to arrive at the equation necessary to find this answer, we can also use proportions to obtain: $(\frac{3v}{v})^2(L_f-L_0)=2(2L_f-L_0)$ $(\frac{9}{1})(L_f-L_0)=2(2L_f-L_0)$ $L_0=\frac{5}{7}L_f$
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